A force of 10 N is applied to an object, causing it to move 5 m in the direction of the force. Calculate the work done.
$$W = \Delta KE$$
$$W = F \cdot s$$
$$W = 10 \cdot 5 = 50 J$$
Using the formula $W = F \cdot s$, we get:
$$v^2 = u^2 + 2as$$
$$s = \frac{u^2}{2a} = \frac{4^2}{2 \cdot \frac{5}{2}} = \frac{16}{5} m$$
A force of 10 N is applied to an object, causing it to move 5 m in the direction of the force. Calculate the work done.
$$W = \Delta KE$$
$$W = F \cdot s$$
$$W = 10 \cdot 5 = 50 J$$
Using the formula $W = F \cdot s$, we get: dc pandey physics class 11 pdf download part 1 work
$$v^2 = u^2 + 2as$$
$$s = \frac{u^2}{2a} = \frac{4^2}{2 \cdot \frac{5}{2}} = \frac{16}{5} m$$ A force of 10 N is applied to