Jav G-queen Access

The backtrack method checks if the current row is the last row, and if so, adds the current board configuration to the result list. Otherwise, it tries to place a queen in each column of the current row and recursively calls itself.

The space complexity of the solution is O(N^2), where N is the number of queens. This is because we need to store the board configuration and the result list. jav g-queen

Given an integer n , return all possible configurations of the board where n queens can be placed without attacking each other. The backtrack method checks if the current row

private void backtrack(List<List<String>> result, char[][] board, int row) { if (row == board.length) { List<String> solution = new ArrayList<>(); for (char[] chars : board) { solution.add(new String(chars)); } result.add(solution); return; } for (int col = 0; col < board.length; col++) { if (isValid(board, row, col)) { board[row][col] = 'Q'; backtrack(result, board, row + 1); board[row][col] = '.'; } } } This is because we need to store the

The isValid method checks if a queen can be placed at a given position on the board by checking the column and diagonals.

The N-Queens problem is a classic backtracking problem in computer science, where the goal is to place N queens on an NxN chessboard such that no two queens attack each other.

public class Solution { public List<List<String>> solveNQueens(int n) { List<List<String>> result = new ArrayList<>(); char[][] board = new char[n][n]; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { board[i][j] = '.'; } } backtrack(result, board, 0); return result; }